I really need help in connections Geometry Unit 5 lesson 9 Surface Area and Volume Unit test please?!?!? Im having a really hard time and anyone willing to help it would be greatly appreciated!!
Can you give an example of one of the problems that you're having issues with?
I'm basically having issues with most of them. Math definitely isn't my stronger subject.
Find the lateral area and surface area of the cone. Round the answers to the nearest tenth. The figure is not drawn to scale. (1 point) L.A. = 395.8 ft2; S.A. = 791.7 ft2 L.A. = 1,583.4 ft2; S.A. = 1,244.1 ft2 L.A. = 622.0 ft2; S.A. = 791.7 ft2 L.A. = 791.7 ft2; S.A. = 1,244.1 ft2
That's only one of them.
Okay, well' let's do that one first. :)
Please. xD
|dw:1367446549397:dw|-- So, I flipped the cone there. And if you look at the cone, the base is a circle. And if you draw a line from the radius to the top of the cone, you get a triangle. Do you see that? [And sorry if my explanations aren't so great; not so great with Geometry]
That's alright- me either, obviously! Yes, I see it. Isn't there a formula for calculate the surface and linear areas of a cone though? I was having a hard time recalling it.
Yes. :)
Do you know what the formulas are?
Surface Area of a cone is:\[SA = \pi r s + \pi r^2\] It's basically the area of the base and the area of the cone added together. r = the radius, and s = the side of the that we were given.
Okay, so I can try to solve it then.
r = 12 s = 21 3.14 x 12 x 21 = 791.28
3.14 x 12^2 = 3.14 x 144 3.14 x 144 = 452.16
Lateral Area of a cone is: \[LA = \pi r L\] where r is the radius, L is the slant height of the cone.
wouldn't the slant height be 21?
I believe that the answer is D. Thanks for your help. (:
\[SA = \pi(12)(21)+\pi(12)^2\]\[=791.681 + 452.389\] = 1244.1 And yes, the slant height is 21. :)
Thanks for your help (:
You're welcome Does it make sense now?
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