How do you write an equation for the line passing through points (3,1) and (-2,6).

Question

jdoe0001 · Answer

anonymous · Answer

-1

jdoe0001 · Answer

jdoe0001 · Answer

say pick the 1st ordered pair, and use -1 as your 'm', slope

anonymous · Answer

I plugged in using point (3,1) and getting answer y= -1x+4...not sure if the -1x is correct.

jdoe0001 · Answer

well, => y-(1) = -1 (x-3)  $
\implies y-1=-x+3 \implies y=-x+3+1 \implies y=-x+4 \ OR \ {\bf y=4-x}
$

jdoe0001 · Answer

hmmm

jdoe0001 · Answer

well, => y-(1) = -1 (x-3) 
$$
\implies y-1=-x+3 \implies y=-x+3+1 \implies y=-x+4 \ OR \ {\bf y=4-x}
$$

anonymous · Answer

okay...see what I'm doing wrong! Thank you so much...can go test now!