Question

Can someone please check my answer that I got please

Answer 1

I got choice A as my answer

Answer 2

no. it is not A.

you must use the chain rule

d u^n is n* u^(n-1) * du

Answer 3

ok hold on let me redo it

Answer 4

so you should get
\[ 4 (2x^2+1)^3 \cdot d ( 2x^2 + 1) \]

Answer 5

ok I got choice E as the final answer correct?

Answer 6

as posted up above it is
\[ 4 (2x^2+1)^3 \cdot \frac{d}{dx} ( 2x^2 + 1) \]

what is
\[ \frac{d}{dx} ( 2x^2 + 1) \]?

Answer 7

is choice c the answer I just redid it again

Answer 8

yes
\[ \frac{d}{dx} ( 2x^2 + 1) = 2 \frac{d}{dx} x^2 + \frac{d}{dx}1 = 2 \cdot 2 x +0= 4x\]
so the answer is
\[ 4 (2x^2+1)^3 \cdot \frac{d}{dx} ( 2x^2 + 1) = 4 (2x^2+1)^3 \cdot 4x \\ =16x(2x^2+1)^3 \]

Answer 9

ok thanks