Write the equation of the line that is perpendicular to the line y = 2x + 2 and passes through the point (6, 3).

Question

terenzreignz · Answer

To understand this question, we need the concept of slopes.  What is the slope of the line 
y = 2x + 2 ?

anonymous · Answer

Yeah

anonymous · Answer

The slope of the perpendicular line will be the negative reciprocal of the slope in the given equation. Then you just need to write the equation for the perpendicular as y = mx + b, where m is the slope (negative reciprocal of  the slope of the given equation), and then plug in the given point for x and y and then solve for b. That will give you the equation of the perpendicular going through the given point.

@manueld167

anonymous · Answer

y = 2x + 6

 y = −x + 3

 y = −x + 6

 y = 2x + 3?

anonymous · Answer

-1/2x*

anonymous · Answer

Yes the slope will be -1/2. So our equation of the perpendicular line will look something like y = -1/2x + b. We don't know what be is though, but we know that the line goes through (6, 3). So plug in 6 for x and 3 for y and then solve for b. After you have b, you will have the complete equation.