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Mathematics 8 Online
OpenStudy (anonymous):

Can someone please check my answer

OpenStudy (anonymous):

OpenStudy (anonymous):

I think the answer is choice E is that correct?

OpenStudy (moonlitfate):

I got D. :)

OpenStudy (moonlitfate):

Is this for a Calculus class, by chance?

OpenStudy (anonymous):

yes

OpenStudy (moonlitfate):

Okay. Well, let's start off at the beginning. Do you know how to take the derivative of that function?

OpenStudy (anonymous):

yup

OpenStudy (moonlitfate):

Okay! Then you should all ready know that \[f'(x) = \frac{ -25 }{ (4x-3)^2 }\]

OpenStudy (anonymous):

yup

OpenStudy (anonymous):

I hate to interrupt but I have got to go sorry something came up

OpenStudy (moonlitfate):

So, to find the tangent line, the second to do is the find the slope of the line. What you're to do is plug in the x-value of the point you were given in into f'(x), and the answer you get is the the slope of the line.

OpenStudy (moonlitfate):

It's all right.

OpenStudy (moonlitfate):

After that, you are going to use the slope (m), the given point, and the point-slope formula to find the equation of the line tangent to the graph at the given point. :) Hopefully, that makes sense. If not, then let me know when you're back, and I can show you how it's done.

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