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OpenStudy (anonymous):
OpenStudy (anonymous):
I think the answer is choice E is that correct?
OpenStudy (moonlitfate):
I got D. :)
OpenStudy (moonlitfate):
Is this for a Calculus class, by chance?
OpenStudy (anonymous):
yes
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OpenStudy (moonlitfate):
Okay. Well, let's start off at the beginning. Do you know how to take the derivative of that function?
OpenStudy (anonymous):
yup
OpenStudy (moonlitfate):
Okay! Then you should all ready know that \[f'(x) = \frac{ -25 }{ (4x-3)^2 }\]
OpenStudy (anonymous):
yup
OpenStudy (anonymous):
I hate to interrupt but I have got to go sorry something came up
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OpenStudy (moonlitfate):
So, to find the tangent line, the second to do is the find the slope of the line. What you're to do is plug in the x-value of the point you were given in into f'(x), and the answer you get is the the slope of the line.
OpenStudy (moonlitfate):
It's all right.
OpenStudy (moonlitfate):
After that, you are going to use the slope (m), the given point, and the point-slope formula to find the equation of the line tangent to the graph at the given point. :) Hopefully, that makes sense. If not, then let me know when you're back, and I can show you how it's done.