Question

ln x + ln(x+3) = ln10

Answer 1

@RadEn

Answer 2

for left side, it can simplified b using the property of log
ln x + ln(x+3) = ln x(x+3)
now u have

ln x(x+3) = ln 10

cancel out the ln from both sides, giving us
x(x+3) = 10
x^2 + 3x - 10 = 0
solve for x
(hint : this can be factored)

Answer 3

thank you can you help me with another one again?

Answer 4

:)

Answer 5

i have to go to school now, if not i can come late :)

Answer 6

np ^^

Answer 7

see u ;)

Answer 8

m'kay :)

Answer 9

well, i want continue for the rest
x^2 + 3x - 10 = 0
(x+5)(x-2) = 0
the zeroes satisfies if x+5 = 0 or x-2 = 0
we get x = -5 or x = 2

Answer 10

but we have to check of them again. we subtitute them to the original equation :
ln(x) + ln(x+3) = 10

if x=-5
we have ln(-5) + ln(-5+3) = 10
actually, it does not can be a solution for x = -5, because the log(x) would be undefined.

if x = 2
we have ln(2) + ln(2+3) = ln 10
it can be a solution because ln(x) defined for x = 2

thus, the solution is only x = 2