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how would you solve: (square root 3x+4)-( square root 2x-4)=2
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start with \[\sqrt{3x+4}=2+\sqrt{2x-4}\] and then square both sides
that will give you \[3x+4=4+(2x-4)+4\sqrt{2x-4}\] now put everything without a radical on the left and square again
you get \[x-4=4\sqrt{2x-4}\] before you square
if you square the right you would have to foil right?
lol yeah, foil i.e. multiply
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lol at the image
ok cool ty :) that helped alot
don't forget to check for wrong answers
yw
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