Find the volume of the pyramid the answer is __/_sqrt_ https://media.glynlyon.com/g_geo_2012/8/groupi77.gif
do you need to know anything?
ok the the height is 4 and the base is 16
right
yea the base is a triangle
im not too sure how to find it out thought because i'm incredibly stupid when it comes to geometry
equilateral triangle with sides of 4
does the link not work??? thats the picture of what it looks like
erm i think it is 4 unless that is the slant height the only lengths given is is 4 and theres like 5 lengths with a measure of 4
i post the link again maybe itll work
oh it doesnt give you the height then
yea so each side length is 4
i know that but i dont know where to go from there
omg lol im so lost lol this stuff is way to complex
>.>
v- lxwxh
this is part of a online course im taking as a summer school class so thats why i dont know anything and the lessons they give you sucks and doesnt explain anything
but how does that help me on a different shape because its a different formula
yea volume of a cube is length *width*height
yea cube is easy a traingle not so much
so its 16....right?
the lengths they give you for the base is 4 and 4 which would mean it would be 16
so drop an line to make it a right triangle
ok can u tell me what the height is now
the measure below the angle is 2 right
yes
so the height is 4 i think
dong the pytahg theorem 2sq=4sq 4/16 = 4
height is Sqrt of 12 >_>
area oh base = 4*sqrt12/2 = 2sqrt12
i thought it was asq+bsq=csq then u just divide it out lol
i hate math so much just for this reason so annoying
volume of pyramid = area of base * height/3 = 2sqrt12*sqrt12/3 = simply this
math is really easy
you are just overthinking everything
ok right so
would you multiple the 12 inside the swrt by each other?
yea
the answer is ___/_sqrt_
yes
Volume of a pyramid is given by V = (1/3) x Height x Area of base Let the side of basal equilateral triangle be 'a' and the height be 'h'. Area of base = (√3a^2)/4 Hence, V = (1/3) x h x (√3a^2)/4 = (√3ha^2)/12. If all the faces of the pyramid are equilateral triangles (i.e. tetrahedron) then a^2 = h^2 + {(2/3)(√3a/2)}^2 a^2 = h^2 + (a/√3)^2 a^2 = h^2 + (a^2)/3 h^2 = a^2 - (a^2)/3 = (2/3)a^2 h = √(2/3)a So, V = (√3a^2)/12 x √(2/3)a = (√2a^3)/12
we did something wrong then because that answer doesnt fit the thing
its ___divided by _then sqrt_
(√2*4^3)/12 = √128/12
that is your answer
doesnt fit
128 fills the 3 blanks
its divided by 1 blank then to the side its sqrt something
hey i will just giive u a brief explaination u shud be able to do it frmo there
STEPs 1)First find the area of the base(the triangle on the bottom) of the pyramid 2)Find the midpoint of the Triangle 3)Then find the height of the triangle with sides 4 and base = the length of the midpoint to the length of the corner of the triangle(i will show u a picture of this) 4)Now multiply the area of the base times the height found in step 3 and divide by 3
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