Question

how do you find limits when x-->infinity?

Answer 1

Let's say
\[\lim_{x \rightarrow \infty}\frac{1}{x+3}\]
As x becoming huge, then the denominator become very large and makes the fraction zero because it's such a small number.

Another example:
\[ \lim_{x\to \infty } 3 x^2 =\infty\]
As x is becoming too large, the whole thing becomes infinity

Answer 2

so if i were to have 9x^4+3/4x^4...would the limit be 9/4?

Answer 3

Another example:
\[\lim_{x\to \infty } \frac{3 x^2 }{x^3+5}\]
x at the bottom grows faster than the one on top, so denominator is huge, then it is zero

Answer 4

Yup
\[\lim_{x \rightarrow \infty} (\frac{9x^4+3}{4x^4}) \\ \\ \lim_{x \rightarrow \infty}(\frac{9}{4}+\frac{3}{4x^4}) \\ \\ \frac{9}{4}\]

Answer 5

yay :D thanks so much!

Answer 6

welcome :)