1. Find the area of the regular polygon. Give the answer to the nearest tenth. pentagon with a side of 6 m (1 point) 123.9 m² 12.4 m² 61.9 m² 49.5 m²
The answer is 61.9m^2, do you need me to show you the steps of how to do it?
Do you know the distance from the center of a side to the center?
yeah thatd be nice
Because the formula for area is, \[A = \frac{5}{2} s a\]
oooooooo lol okay
That help? You have a pic of the problem that you are working on? Or draw it?
the one i posted after i asked the second question. and i accidently clicked an answer so thats not the answer i picked lol
huh?
this one lol
Well, the minor arc is 50 degrees. You have the point D out to the side. So, to go from A, to D, to B would be 360 degrees for the whole circle minus the part that you don't cover, the 50 degrees. Did that make sense?
so it would be 310?
so c?
correct!
sweet! lol okay i have more
so would you do 8% of 360?
and id be a??
.08*360
i dont have a calculator on me atm, sorry, but it should be .08*360
and that equals 28.8 lol
alright, then that should be the angle then.
is this d?
Yes, for circumference it is pi times diameter
mkay i got a couple more is that okay?
Ok, on this one, we are looking for 3/4 of the circle. The radius is 6, so the diameter is 12.
okayy
\[C = \pi d\] In this case we want\[(\frac{3}{4})(C) = (\frac{3}{4})(\pi d)\]
9 pi?
Should be!
yay lol okay
For this one, you are going to want to find the area of the entire circle, and then find the area of the smaller internal circle. Then subtract the smaller circles area from the larger circles area.
thats confusing..
Ok, the diameter for the large circle is 5.4+2.2. The radius is (5.4+2.2)/2. That is the large circle's radius. The area of a circle is \[A = \pi r^2\] So you would have \[A_1 = \pi (\frac{5.4+2.2}{2})^2\] The smaller circles diameter is 5.4, so the radius is 5.4/2. \[A_2 = \pi (\frac{5.4}{2})^2\] The area of the decking would be \[A_{decking} = A_1 - A_2\]
Make any more sense?
kinda
could you calculate the area of the whole circle for me?
i think i got 132.73
or mayby 45.36? idk i suck at math
i got 45.3645979
k lol
then, we need to find the second area
k hold on
22.90?
Correct! Now you need to subtract that value from the value we found before.
22.46
Which when rounded to the tenth is?
d
Um... yeah... somehow we got off by a few tenths.... idk, D should be the correct answer.
okayy lol.. 2 more
Ok, for problem number 9. We are given an arc of a circle, that is 140 Degrees. We are given the radius. We can give the area of a circle as \[A = \pi r^2\] We want the ratio of 140 degrees to 360 degrees... or in other words 140/360. Can you find that for me?
umm a=254.5
the other one is 31.5.. would that be the answers?
that is the area of the whole circle. We want just the area in the arc of 140 degrees which is 0.388888889 of the whole circle. So we would take the answer you got, of 254.5 and multiply it by 0.38888889 to get 98.960, or in other words 99.
ohhh okayy lol
On the last one, I am a bit rusty on the geometry... I am thinking of how to solve it right now.
ok lol
We are asked to find the area of a segment. Which is that little shaded sliver of the circle. First we need to find the height of the triangle. Are you familiar with the cosine rule?
nope
Ok, The law of cosines is given as, \[c^2 = a^2 + b^2 - 2 a b \cos (C)\] |dw:1367506341159:dw|
C is my backspace button doesnt work...
wtf...
brb
what? lol
oka y
i can type and it doenst work
Much better!
haha okay
ok, so c is the straight line that is across the segment of the circle, and C is 120 degrees. a and b are the radius. Do you think that you could find the length of the line?
no.. ll
Ok, we have this here, |dw:1367506812158:dw| Ignore how badly drawn it is. We have a=24 b=24 C=120 deg c=? when we plug that into the formula we have \[c^2 = 24^2+24^2 - 2(24)(24)(\cos(120))\]
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