Question

I don't get this!!! Help?!

Answer 1

what is it

Answer 2

\[\sqrt{\frac{ 68x ^{15}y ^{9} }{ 7xy ^{11} }}\]

Answer 3

um? i am sorry i dont know

Answer 4

what kind of math is this????

Answer 5

It's okay :/ algebra

Answer 6

1 or 2

Answer 7

1

Answer 8

I can help in one minute

Answer 9

oh well sorry i took that already and i am terrible at it i would get you a bad grade

Answer 10

@.Sam. @Notamathgenius @saifoo.khan @Eyad

Answer 11

\[\sqrt{68x^{15}y^9\over7xy^{11}}\]First let's cancel each of the components.\[{x^{15}\over x } = x^{14}\] \[y^9/y^{11} = y^{-2}\] Giving us \[\sqrt{68x^{14}y^{-2}\over7}\]with me so far?

Answer 12

Ah sorry @UnkleRhaukus please continue.

Answer 13

(if you want)

Answer 14

i was just gonnna say \[\sqrt{\frac{ 68x ^{15}y ^{9} }{ 7xy ^{11} }}=\sqrt{\frac{ 68x ^{15-1}y ^{9-11} }{ 7 }}\]
but you continue @hea

Answer 15

Okay, yea...

Answer 16

Alright, cheers, mate. So now we can square root each bit individually (because they are all multiplied together)\[\sqrt{{68x^{14}y^{-2}\over 7}}\] \[\sqrt{x^{14}} = ?\]

Answer 17

\[\sqrt{x^{14}} = (x^{14})^{1/2} = x^7\]

Answer 18

Would that be \[x ^{7} \]

Answer 19

Yeah!

Answer 20

okay...

Answer 21

\[\sqrt{y^{-2}} = ?\]

Answer 22

tswizzle give hea a medal i will give you one for wanting to learn

Answer 23

Ok well \[\sqrt{y^{-2}} = (y^{-2})^{1/2} = y^{-1}\]does that make sense?

Answer 24

haha, cheers @loser123456789876 !

Answer 25

Oh she's gone. @TSwizzle ?

Answer 26

Well, assuming you understand what we have done. So far we have \[\sqrt{68\over 7}x^{7}y^{-1}\]Now 68 can be rewritten as \(4 \times 17\) so \[\sqrt{{4\times17 \over 7}} =2\sqrt{17/7}\]. So eventually we have \[2\sqrt{17/7}x^7y^{-1}\]

Answer 27

Hope that helps!

Answer 28

I am a he and i am copying a form for camp

Answer 29

@hea can you give TSwizzle a medal for wanting to learn

Answer 30

Sorry, lost internet connection. Thanks that helps a lot.

Answer 31

That's not one of the options...It's a multiple choice question.

Answer 32

remember that \[y^{-1} = {1\over y}\]

Answer 33

If you're still struggling it might be worth putting the choices.