Question

NEed Help MEdalss!!!!!

Answer 1

Find the eqaution of each line in slope intercept form

Throught he point (6,1) with slope=1/3

Answer 2

the equation in slope point form is
y -y1 = m (x-x1)
where m = slope,
x1,y1 is the point

Answer 3

y-1 = 1/3(x-6)

3y-3=x-6

x-3y-3=0

Answer 4

first find equation in that form, then you can isolate y to get it in slope intercept form.

Answer 5

Hope that helps! :)

Answer 6

So how do i find it in that equation form? Thnx @Rosy333

Answer 7

You've understood it?

Answer 8

Ive got the equation but i was trying to understand how you got there?

Answer 9

can you explain? :/

Answer 10

?

Answer 11

That is a basic formula which you are supposed to remember! y-y1=m(x-x1) where m=slope

Answer 12

so what would Y be? because i thought the slope wouldve been y

Answer 13

and for slope intercept form, u need to isolate y
y-1 = 1/3(x-6)
y = x/3 -2+1
y=x/3 -1

Answer 14

y is not slope, m= slope

Answer 15

oh okay i get it
:)

Answer 16

y-y1=m(x-x1) where m=slope, so just remember this formula for problems like this than

Answer 17

yes/no/maybe so?

Answer 18

thanks anyways

Answer 19

we can create a parallel line that passes thru the origin (0,0) as:\[y=\frac13x\]
in order to move the point (6,1) to the origin, we would have to subtract 6 from the x component, and subtract 1 from the y component:\[(6-6,1-1)=(0,0)\]
but, we do not just want to move that single point, we want to move ALL the points (x,y) from that line, so in general:\[(x,y)\to (x-6,y-1)\] is our translation:\[(y=\frac13x)\to (y-6=\frac13(x-1))\]