The cost of manufacturing x items is given by C(x) = 0.02x^2 + 20x + 1800. Find the marginal cost function. Compuare the marginal cost at x = 2- to the actual cost of producing the 20th item.
@UnkleRhaukus can u help?
@amistre64 @Best_Mathematician can u help?
ok
marginal cost is the derivative of cost
so i should take the derivative of that?
yes
okay
actual cost of nth item: C(n) - C(n-1) marginal cost of nth item: C'(n)
okay got it
ait is this derivatives
Best mistook 2- as something other than a typo ... but was on the right track
yea its positive 2 sorry
the marginal cost of the 20th item is, the rate of change in cost of the 20th item actual cost is the extra amount that the 20th item costs compared to the actual cost of the 19th item
so marginal cost and actual cost r 2 different things
so after i find the derivative i should plug in 20 into C'(x) to find the marginal cost for 20th items.??
thats correct, the word marginal in finance relates to derivatives
yes, C'(20) = marginal cost at x=20
okay
got it...not a business major but i do have great interest in business
so that would be my actual cost or?
for actual cost simply plug in values for marginal cost plugin values in derivatives
okay
\[actual~cost=\frac{C(b)-C(a)}{b-a}\] \[marginal~cost=\lim_{a\to b}\frac{C(b)-C(a)}{b-a}\]
okay i see
so its asking me for the cost function... For the cost function in problem 2, find the value of x which minimized the average cost
@amistre64 @Best_Mathematician @electrokid can u help with the second question?
new question => new post
ok
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