Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
2(2r+xr)=8a
OpenStudy (anonymous):
r=a/sinx
OpenStudy (saifoo.khan):
Or do you mean 2(2x+xr) = 8a ?
OpenStudy (anonymous):
The
perimeter of the sector AMN is equal to half the perimeter of the rectangle.
OpenStudy (saifoo.khan):
Ah! RIGHT! I made a mistake.
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
ohh sorry tehre 2r instead of 2x
OpenStudy (saifoo.khan):
Whats next?
OpenStudy (anonymous):
substitute
2(2r+xr)=8a
4r+2xr=8rsinx
OpenStudy (anonymous):
divide by 2r
OpenStudy (anonymous):
2+x=4sinx
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
sinx =
1
4
(2+x).
OpenStudy (saifoo.khan):
Awesome!
What about part (ii) ?
OpenStudy (saifoo.khan):
In part (ii), we just have to insert 0.8?
OpenStudy (saifoo.khan):
Wait. i got it.
OpenStudy (saifoo.khan):
Thanks @SerikMB
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
how did u solve it?
OpenStudy (anonymous):
just substitute four times?
OpenStudy (saifoo.khan):
first insert 0.8, then insert the answer back, then insert the answer again.
We will get a series of answers.
0.7754
0.7668
0.7638
0.7628
Since we needed the answer correct to 2dp, so our answer will be 0.76
OpenStudy (anonymous):
thx u too
OpenStudy (saifoo.khan):
np
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (saifoo.khan):
Wanna try q4?
OpenStudy (anonymous):
sorry, i didn't notice ur reply, well it's very easy but quite tedious
\[\tan(30+\theta)=2\tan(60-\theta)\]