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Mathematics 6 Online
OpenStudy (anonymous):

For the cost function in problem 2, find the value of x which minimized the average cost

OpenStudy (anonymous):

OpenStudy (anonymous):

@electrokid can u help?

OpenStudy (amistre64):

take the average cost, and derivitive it

OpenStudy (amistre64):

...not that im tryng to step on the electroids toes :)

OpenStudy (anonymous):

enjoy, my friend. :)

OpenStudy (amistre64):

this was it right? \[avgCost =\frac{0.02x^2+20x+1800}{x}\]

OpenStudy (amistre64):

avg'= (xC' - C)/x^2 , so essentially when xC' - C = 0

OpenStudy (amistre64):

(0.02(2x^2)+20x)-(0.02x^2+20x+1800)=0

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

okay i see thanks!

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