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Mathematics 19 Online
OpenStudy (anonymous):

Last question of the day.. picture will be attached

OpenStudy (anonymous):

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OpenStudy (anonymous):

Line QR II XZ. So can u prove YQR similar to YXZ ?

OpenStudy (anonymous):

umm i haven't done questions like these since the beginning of the year.. i dont really remember how to do it

OpenStudy (anonymous):

ok can u observe that QYR and XYZ are actually the VERY same angle?

OpenStudy (anonymous):

o i guess so

OpenStudy (anonymous):

and actually QR II XZ so YQR equals YXZ since they are corresponding equal angles.

OpenStudy (anonymous):

oh yea wait u need to do a proportion right? big triangle and small triangle?

OpenStudy (anonymous):

thats how it is done. But we have already proved two pairs of angles i.e. YQR = YXZ and QYR = XYZ, so u can say that triangle YQR is similar to triangle YXZ. by AA

OpenStudy (anonymous):

yea

OpenStudy (anonymous):

hence the CORRESPONDING sides will be proportional. but easier way, YQR is similar to YXZ. u can write the corresponding letters as a ratio. so YQ/YX = QR/XZ = YR/YZ. u can try to find RY now? (i mean if 123 is similar to 456 then 12/45 = 23/56 = 13/46 like tht)

OpenStudy (anonymous):

so.. it will be.. 7/x = 14/6 or..?

OpenStudy (anonymous):

actually, lets take YQ/YX = YR/YZ. so YQ = 6 but YX = XQ + YQ which is 6+14 = 20. and YR = x however YZ = YR + RZ = X+7 Hence, 6/20 = x/x+7.,

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

thnx i got the answer, 3!

OpenStudy (anonymous):

yes good :)

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