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Chemistry 16 Online
OpenStudy (anonymous):

can someone explain stoichiometry to me please?

OpenStudy (aaronq):

what exactly about it?

OpenStudy (anonymous):

I don't understand anything about it. :(

OpenStudy (aaronq):

okay, well, in chemical reactions, everything is dealt with in terms of moles. do you know what a mole is?

OpenStudy (anonymous):

kind of.... but not really.

OpenStudy (aaronq):

a mole is just a number, an amount. just like a dozen means 12, a mole means 6.023x10^23 so if you have a dozen of doughnuts, you have 12 doughnuts and if you have a mole of doughnuts, you have 6.023x10^23 doughnuts

OpenStudy (anonymous):

okay that makes sense and that's a lot of doughnuts haha!

OpenStudy (aaronq):

lol well it's just to illustrate so if you have a reaction A -> 2B 1 mole of A will give you 2 moles of B I wanna point out that you have to convert to moles ALWAYS (except maybe with ideal gases) because moles are not proportional to mass. for example, 1 mole of hydrogen is 1 g/mol and 1 mole of He is 4 g/mol

OpenStudy (anonymous):

you lost me haha!

OpenStudy (aaronq):

lol okay.. so you have chemical equation for combustion: C2H4 + 3O2 -> 2CO2 + 2H2O i already balanced it, (do you know how to balance them?) lets say i tell you how much ethene (C2H4) did i burn if i made 30 L of CO2 gas? how would you do it?

OpenStudy (anonymous):

im confused about what you're asking

OpenStudy (aaronq):

given the equation above, if you produced 30 L of CO2 gas, how much C2H4 did you burn?

OpenStudy (aaronq):

well i'd suggest you watch some vids, http://www.youtube.com/watch?v=FSyAehMdpyI&list=PL8dPuuaLjXtPHzzYuWy6fYEaX9mQQ8oGr and look up chemistry one's on khan academy

sam (.sam.):

By far I used fractions to solve these http://www.kentchemistry.com/moviesfiles/chemguy/advanced/ChemguyStoich.htm

OpenStudy (anonymous):

thank you both :)

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