Question

how do you solve 2(x + 5) > 8x – 8 for X?

Answer 1

well inequalities are not solved; they just have a range that is why they are called inequalities.

and if we consider that X is a real number,

then 2(x+5) > 8x-8

2x+10>8x-8

18 > 6x if u can find x

Answer 2

I'm not sure how to put it in a number line? @luckythebest

Answer 3

well it depends on the set..is it real numbers or integers or what

Answer 4

real numbers @luckythebest

Answer 5

ok u find 3 > x .

Since its real numbers means that there are infinitely many numbers including decimals and fractions.

The set is presented as - {x : 3 > x, x belongs to R }

We have NO solution set since it includes millions and zillions of numbers,

Hence we plot it on number line as -

(A darkened circle means x is included in 3; however 3 > x not 3 >= x and hence X CANNOT be 3, so I will use a non-darkened circle to show that)

Answer 6

this is how the set is.

Answer 7

no I mean, what number do I put in the number line for the equation?

Answer 8

1st of all; this is NOT a equation.

Equation has = sign, inequality has > or < or >=, <= sign.

u will only mark 3 and area less than that, not including 3 in the set. thats all u have do while plotting it on number line.

Answer 9

ahh how'd you get 3 for 2(x + 5) > 8x – 8

Answer 10

I got 3 > x, not 3 = x

2(x+5) = 2x+10

so 2x+10 > 8x-8

shifting -8 to left, and 2x to the right,

8+10 > 8x-2x

18 > 6x.

dividing both sides by 6 -

18/6 > 6x/6 => 3 > x.

Answer 11

oh I see, okay thanks, appreciate all the help.