Question

Simple Geometry questions-

The area of the triangle shown below is 80 cm2. Find the value of x. (The figure is not drawn to scale.) - (Will post first image)
A. 8
B. 16
C. 32
D. 160


2. Five times the width of a certain rectangle exceeds twice its length by one inch, and three times its length is ten more than its perimeter. Find the width of the rectangle.
21 inches
10 inches
42 inches
52 inches

Answer 1

So you know that area of triangle = 1/2 x base x height?

Answer 2

It has already given me the area of the triangle... 80. I need to solve for x

Answer 3

solve for x
1/2 * 10 * 2x = 80

Answer 4

I already know that it's 80.

Answer 5

yeah so as rad said...1/2 x 10 x 2x = 80.

which makes it 10x = 80. if u can solve for x now

Answer 6

I'm trying to get someone to show me HOW to solve for x.

Answer 7

Yeah so ^ it is.

Area of triangle = 1/2 bh.

1/2 bh = 80

bh = 160

10 x 2x = 160

20 x = 160 hence x = 8 , which is how it is solved? :P

Answer 8

Thanks.. Do you know what my other answer is?

Answer 9

That was confusing..

Answer 10

ok i'll make it easy.

Five times the width of a certain rectangle exceeds twice its length by one inch, and three times its length is ten more than its perimeter. Find the width of the rectangle.

So let our width be X inches, and length be Y inches.

Now 5 times width would be 5X, and this exceeds twice length which is 2Y by 1 inch.

So we can say, 5X = 2Y + 1 ok?

Answer 11

Okay..?

Answer 12

Yeah.

Now three times its length is ten more than its perimeter.

the perimeter of rectangle is 2(x+y) where x = width and y = length.

Now 3 times length = 3Y.

and 3Y is 10 more than perimeter.

so 3Y = 2X + 2Y + 10

so -10 = 2X - Y; ok till here?