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How do you find the integral of 4/(x^2+2x+5) using trig substitution?
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start by completing the squares for the denominator
okay; that makes sense now. thanks!
anymore questions?
no :) I just didn't know how to start the problem.
\[4 \int\limits \frac{1}{x^2+2 x+5} \, dx\] CTS \[4 \int\limits \frac{1}{4+(x+1)^2} \, dx\] Factor 4 \[ \int\limits \frac{1}{ \left(1+\frac{u^2}{4}\right)} \, du\] Trig substitution here
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ok, thanks. so it would be 2arctan((x+1)/2) + c
Yes.
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