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Mathematics 7 Online
OpenStudy (anonymous):

Based on this figure which statement proves that the opposite angles of an inscribed quadrilateral are supplementary? My answer is: a = 2 × angle KJM, b = 2 × angle KLM, and a + b = 360°.

OpenStudy (anonymous):

OpenStudy (anonymous):

@AravindG @luckythebest

OpenStudy (anonymous):

so 2 KJM + 2 KLM = 360 so ur correct :)

OpenStudy (anonymous):

and its "cyclic quadrilateral." an inscribed quadrilateral may have centre as a vertex where sum of opp. angles will NOT be 360.

OpenStudy (anonymous):

wait, that's how the question goes...

OpenStudy (anonymous):

So, I'm wrong? Because it doesn't equal 360?

OpenStudy (anonymous):

@luckythebest @AravindG

OpenStudy (anonymous):

"Cyclic quadrilateral" means a quad. with ALL 4 VERTICES touching circle. ur figure shows a cyclic quad. Inscribed quad is this - |dw:1367554317150:dw| so ur actually correcto :)

OpenStudy (aravindg):

a+b=360 no doubt about that

OpenStudy (anonymous):

but this is an inscribed quad.

OpenStudy (aravindg):

Whatever it is a+b completes a full circle of rotation .That means the angle will be 360 degree

OpenStudy (anonymous):

But these are all the possible answers, I chose the third one though. Angle KJM is a, angle KLM is b, and a + b + angle JKL + angle LMJ = 360°. Angle KLM is a, angle KJM is b, and a + b + angle JKL + angle LMJ = 360°. a = 2 × angle KJM, b = 2 × angle KLM, and a + b = 360°. a = 2 × angle KLM, b = 2 × angle KJM, and a + b = 360°

OpenStudy (anonymous):

3rd is correcto

OpenStudy (aravindg):

3rd is the right one

OpenStudy (anonymous):

Okay, just making sure!!

OpenStudy (aravindg):

:)

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