How would you find arctan(-1)?
do you have a unit circle diagram with you?
yes
Know the range of arctan, -pi/2 to pi/2, so the answer is -pi/4
ok can you tell me where both sine and cosine are equal...but are different in sign
3pi/4
wrong
that's correct
3pi/4 is out of the range for arctan
tan(3pi/4) = -1
It's -pi/4
are there any other points where sine and cosine are equal, but opposite in sign?
7pi/4
that's coterminal to -pi/4 because you can subtract 2pi from 7pi/4 to get 7pi/4 - 2pi 7pi/4 - 8pi/4 (7pi - 8pi)/4 -pi/4
So the two angles -pi/4 and 7pi/4 are coterminal, ie they lie in the same position (one is just full rotation away from the other)
But you see, there's range for arctan which is from -90 to 90
yes I'm getting there rman3
it turns out that arctan is a function so you should get EXACTLY ONE output for any given input since tan(x) = -1 has at least two solutions (there's actually infinitely many of them), we need to come up with a way to pinpoint the value of x when we say x = arctan(-1) The convention is to restrict the range of arctan to be -pi/4 <= y <= pi/4 which guarantees we only get one output for any given input
-pi/2 <= y <= pi/2 is the range I meant*
anyways, this is why arctan(-1) = -pi/4 in terms of degrees, arctan(-1) = -45 degrees
Well if you let arctan graph go on forever, it becomes not a function so it is restricted from -pi/2 to pi/2
In my mathematics class, my teacher told us that -45 was a wrong answer. He ended up with 135
looks like he added 180 degrees to -45 to get 135 he probably has a reason for doing that, but not sure
I see
it turns out that all solutions of tan(x) = -1 are separated by 180 degrees, so it's not a coincidence. I'm just not sure why your teacher didn't go with -45 maybe he wanted the first positive solution
first positive solution of tan(x) = -1
yeah, tan of 135 = -1, but if that were the case, should it not equal 135 backwards? ex) tan 135 = -1 but arctan -1 = -45
or am I just mixing up the definition of arctan itself?
by definition, the range of arctan is -90 <= y <= 90 so you saying arctan(-1) = -45 is correct
I'm thinking there's more to the problem than just arctan(-1) though
the full question is: x=arctan (-1)
so, thanks anyways! :D
well then unfortunately your teacher is using arctan wrong if that's all there is
Its a possibility that he is looking for a positive angle instead of a negative one.
true, that's always a possibility and it could be the possibility that he just wants one x value to satisfy tan(x) = -1 and wants that x value to be positive
probably, because -45 also satisfies the equation.
I have to leave, because I need to study other topics, but you should know how grateful I am for your help Thank you.
you're welcome
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