Question

plse solve this

Answer 1

\[\theta=\cos^{-1}\frac{-\sqrt3}{2}\]
\[\cos\theta=\frac{-\sqrt3}{2}\]
So vat is the value of \(\theta\)? @msingh

Answer 2

cos60=1/2

Answer 3

well ya. but there is another value.

Answer 4

-cos30

Answer 5

why do you need to find theta?
It's just cos(A+B)

Answer 6

hw abt 5pi/6?

Answer 7

i mean cos(5pi/6)

Answer 8

okay

Answer 9

\[\cos(\frac{5\pi}{6}+\frac{\pi}{4})=?\]

Answer 10

nw as @apple_pi mentioned u can use \(\cos(A+B)=\cos A\cos B-\sin A\sin B\).

Answer 11

@ajprincess why did you find theta?
You could just leave it as acos(...),
then cos(acos(...)) would cancel and
then use pythagorus to find sin(acos(...))

Answer 12

well i found it easy to find theta first nd then do..:)

Answer 13

ok whatever suits you :p

Answer 14

@ajprincess
can u plse tell me exact answer

Answer 15

Well i am really sorry. I am nt supposed to give direct answers. pls check the code of conduct