How do you factor this equation x^2-5^2
\(a^2-b^2=(a+b)(a-b)\) here, a=x b=5
how did you get to this answer?
thats the general formula that u can use.
no, it would be (x-5)(x+5)
ohhh i see so thats why ive been getting the answers wrong lol
thank you!
welcome ^_^
wait just to make sure i the equation would end up like this right? (x+5)(x-5)
exactly.
but how come the answer ends with the signs switched?
because the formulas say so if you multiply them out, (x+5)(x-5) = x*x -x*5 +5*x -5*5 5x gets cancelled, and you are left with x^2-5^2
ahh so for every problem would i have to switch the signs?
only when its difference of squares, like a^2-b^2
ahh alright so if the equation was like 2x-25 you wouldnt switch it you would leave the answer as (x+5)(x-5)
2x-25 is not of the type a^2-b^2
ahh my bad 5^2-6^2 like the squares have to be the same in order for it to be left alone
5^2-6^2 will then be (5+6)(5-6)
thank you very much!! you helped me out big time :P
most welcome ^_^
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