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OpenStudy (anonymous):
\[6\sqrt{v}-\sqrt{4v^2}-\sqrt{36v}+\sqrt{v^2}\]
OpenStudy (anonymous):
can you simplify\[\sqrt{v^2}\]?
OpenStudy (anonymous):
yea to v
OpenStudy (anonymous):
Great how about \[\sqrt{4v^2}\]?
OpenStudy (anonymous):
yea to v again @hea
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OpenStudy (anonymous):
No. What is the \(\sqrt 4\)?
OpenStudy (anonymous):
2
OpenStudy (anonymous):
Good. When you see a square root with two different things underneath they can be split.\[\sqrt{4v^2} = \sqrt{4}\sqrt{v^2} = 2v\]Does that make sense?
OpenStudy (anonymous):
yea
OpenStudy (anonymous):
Ok, back to your original equation\[6 \sqrt v - \sqrt{4v^2} + \sqrt{36 v} + \sqrt{v^2}\]We have already simplified term 2 and 4. Term 1 (\(6\sqrt v\))is already simplified. So all that is left is the third term.\[\sqrt{36 v}\]Any ideas? Use the same principle as before.
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OpenStudy (anonymous):
Sorry got a sign wrong.\[6 \sqrt v - \sqrt{4v^2} - \sqrt{36 v} + \sqrt{v^2}\]
OpenStudy (anonymous):
6v
OpenStudy (anonymous):
the answer i got is 6v^2
OpenStudy (anonymous):
Not quite. \[\sqrt{36v} = \sqrt{36}\sqrt{v}\]What is the square root of 36?
OpenStudy (anonymous):
6
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OpenStudy (anonymous):
Yep, we can't simplify \(\sqrt v\) any more so we leave that as is. We have now simplified every term. What do we have so far?
OpenStudy (anonymous):
\[v \sqrt{v}\]
OpenStudy (anonymous):
No. we have \[6 \sqrt v - 2v - 6\sqrt{v} + v\]
OpenStudy (anonymous):
Which when we simplify becomes \(-v\)
OpenStudy (anonymous):
oooooo
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