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Mathematics 14 Online
OpenStudy (anonymous):

what is the simplified form of the expression

OpenStudy (anonymous):

\[6\sqrt{v}-\sqrt{4v^2}-\sqrt{36v}+\sqrt{v^2}\]

OpenStudy (anonymous):

can you simplify\[\sqrt{v^2}\]?

OpenStudy (anonymous):

yea to v

OpenStudy (anonymous):

Great how about \[\sqrt{4v^2}\]?

OpenStudy (anonymous):

yea to v again @hea

OpenStudy (anonymous):

No. What is the \(\sqrt 4\)?

OpenStudy (anonymous):

2

OpenStudy (anonymous):

Good. When you see a square root with two different things underneath they can be split.\[\sqrt{4v^2} = \sqrt{4}\sqrt{v^2} = 2v\]Does that make sense?

OpenStudy (anonymous):

yea

OpenStudy (anonymous):

Ok, back to your original equation\[6 \sqrt v - \sqrt{4v^2} + \sqrt{36 v} + \sqrt{v^2}\]We have already simplified term 2 and 4. Term 1 (\(6\sqrt v\))is already simplified. So all that is left is the third term.\[\sqrt{36 v}\]Any ideas? Use the same principle as before.

OpenStudy (anonymous):

Sorry got a sign wrong.\[6 \sqrt v - \sqrt{4v^2} - \sqrt{36 v} + \sqrt{v^2}\]

OpenStudy (anonymous):

6v

OpenStudy (anonymous):

the answer i got is 6v^2

OpenStudy (anonymous):

Not quite. \[\sqrt{36v} = \sqrt{36}\sqrt{v}\]What is the square root of 36?

OpenStudy (anonymous):

6

OpenStudy (anonymous):

Yep, we can't simplify \(\sqrt v\) any more so we leave that as is. We have now simplified every term. What do we have so far?

OpenStudy (anonymous):

\[v \sqrt{v}\]

OpenStudy (anonymous):

No. we have \[6 \sqrt v - 2v - 6\sqrt{v} + v\]

OpenStudy (anonymous):

Which when we simplify becomes \(-v\)

OpenStudy (anonymous):

oooooo

OpenStudy (anonymous):

so thats the answer?

OpenStudy (anonymous):

yeah

OpenStudy (anonymous):

ok thnx!

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