what is the simplified form of the expression
\[6\sqrt{v}-\sqrt{4v^2}-\sqrt{36v}+\sqrt{v^2}\]
can you simplify\[\sqrt{v^2}\]?
yea to v
Great how about \[\sqrt{4v^2}\]?
yea to v again @hea
No. What is the \(\sqrt 4\)?
2
Good. When you see a square root with two different things underneath they can be split.\[\sqrt{4v^2} = \sqrt{4}\sqrt{v^2} = 2v\]Does that make sense?
yea
Ok, back to your original equation\[6 \sqrt v - \sqrt{4v^2} + \sqrt{36 v} + \sqrt{v^2}\]We have already simplified term 2 and 4. Term 1 (\(6\sqrt v\))is already simplified. So all that is left is the third term.\[\sqrt{36 v}\]Any ideas? Use the same principle as before.
Sorry got a sign wrong.\[6 \sqrt v - \sqrt{4v^2} - \sqrt{36 v} + \sqrt{v^2}\]
6v
the answer i got is 6v^2
Not quite. \[\sqrt{36v} = \sqrt{36}\sqrt{v}\]What is the square root of 36?
6
Yep, we can't simplify \(\sqrt v\) any more so we leave that as is. We have now simplified every term. What do we have so far?
\[v \sqrt{v}\]
No. we have \[6 \sqrt v - 2v - 6\sqrt{v} + v\]
Which when we simplify becomes \(-v\)
oooooo
so thats the answer?
yeah
ok thnx!
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