Simplify x/4x+x^2
You can factor the x from the denominator
Which x will be cancelled with numerator and denominator
so it would be something without any xes?
There will be an x left over, look at this \[\frac{x}{4x+x^2} \\ \\ =\frac{x}{x(4+x)} \\ \\ =\frac{1}{4+x}\]
Okay, but could it be 1/x+4 as well?
yes
And that is the answer? Ia m so bad at this. I am doing review for my test and just trying to get some help.
Yea you need to practice more of these especially factoring, you have to make use of cancelling terms in numerators and denominators
Alright, thanks so much! Do you think you can help me with one more?
@.Sam.
ok
Simplify. -14x^3/x^3-5x^4
Again, factor x^3 from denominator, then cancel x^3 for top and bottom
I get -14/-5x^4?
When you factor you gotta remember that both of the terms in the denominator must be factored out \[\frac{-14x^3}{x^3-5x^4} \\ \\ =\frac{-14x^3}{x^3(1-5x)} \\ \\ =\frac{-14}{1-5x}\]
-5x ̂4-14
So the answer is -14/1-5x?
yes
okay. Thanks so much!
welcome :)
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