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Mathematics 21 Online
OpenStudy (anonymous):

Simplify x/4x+x^2

sam (.sam.):

You can factor the x from the denominator

sam (.sam.):

Which x will be cancelled with numerator and denominator

OpenStudy (anonymous):

so it would be something without any xes?

sam (.sam.):

There will be an x left over, look at this \[\frac{x}{4x+x^2} \\ \\ =\frac{x}{x(4+x)} \\ \\ =\frac{1}{4+x}\]

OpenStudy (anonymous):

Okay, but could it be 1/x+4 as well?

sam (.sam.):

yes

OpenStudy (anonymous):

And that is the answer? Ia m so bad at this. I am doing review for my test and just trying to get some help.

sam (.sam.):

Yea you need to practice more of these especially factoring, you have to make use of cancelling terms in numerators and denominators

OpenStudy (anonymous):

Alright, thanks so much! Do you think you can help me with one more?

OpenStudy (anonymous):

@.Sam.

sam (.sam.):

ok

OpenStudy (anonymous):

Simplify. -14x^3/x^3-5x^4

sam (.sam.):

Again, factor x^3 from denominator, then cancel x^3 for top and bottom

OpenStudy (anonymous):

I get -14/-5x^4?

sam (.sam.):

When you factor you gotta remember that both of the terms in the denominator must be factored out \[\frac{-14x^3}{x^3-5x^4} \\ \\ =\frac{-14x^3}{x^3(1-5x)} \\ \\ =\frac{-14}{1-5x}\]

OpenStudy (anonymous):

-5x ̂4-14

OpenStudy (anonymous):

So the answer is -14/1-5x?

sam (.sam.):

yes

OpenStudy (anonymous):

okay. Thanks so much!

sam (.sam.):

welcome :)

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