Question

evaluate: 7!/5!2!

Answer 1

Is it:

\[\frac{7!}{5! \cdot 2!}\]

Answer 2

yes

Answer 3

You can write :

\[7! = 7 \times 6 \times 5!\]

Answer 4

Then cancel \(5!\) in numerator and denominator..

Answer 5

OHHHH! thats how you do it, thank you! :D

Answer 6

You are welcome dear..

Answer 7

What is the answer you got?

Answer 8

1

Answer 9

Wow!!

I mean how??

Answer 10

I HAVE HONESLY NO IDEA, math makes no sense to me, especially Algebra.

Answer 11

7!/5!2!
=7*6*5*4*3*2*1/(5*4*3*2*1*2*1)
=21

Answer 12

\[\frac{7 \times 6 \times \cancel{5!}}{\cancel{5 !} \times 2!} \implies \frac{7 \times 6}{2 \times 1} \implies 21\]

Answer 13

Oh, makes sense!

Answer 14

Keep on making sense..