Question

rewrite over a common denominator: (1)/(1-sinθ)+(1)/(1+sinθ)

Answer 1

\[\frac{1}{1-\sin\theta}+\frac{1}{1+\sin\theta}\]

Answer 2

do you know the answer?

Answer 3

\[=\frac{1+\sin\theta+1-\sin\theta}{\left(1-\sin\theta\right)\left( 1+\sin\theta\right)}\]\[=\frac{2}{\left(1-\sin\theta\right)\left( 1+\sin\theta\right)}\]

Answer 4

\[=\frac{2}{1-\sin^2\theta}\]

Answer 5

you can see the answer now right? it's easy from here.

Answer 6

yes is it 2sec^2Theta?

Answer 7

yup

Answer 8

\[\frac{2}{\cos^2{\theta}}=2\sec^2{\theta}\]

Answer 9

sinθ/cosθ+cosθ/sinθ? complete the identity

Answer 10

not coin it. you haven't medalled me for either question I helped you with.

Answer 11

not doing*

Answer 12

how do i medal you im new to this?

Answer 13

thanks. also you are supposed to create a new question for each one! but I can help you here now anyways.

Answer 14

ok thank you so much

Answer 15

so multiplying to get a common denominator you have \[\frac{\sin^2x+\cos^2x}{\cos x\sin x}=\frac{1}{\cos x\sin x}=\csc x\sec x\]

Answer 16

you are the best

Answer 17

you could also use a double angle identity to get \[2\csc{(2\theta)}\]

Answer 18

not sure if you have learned those or not yet. anyways I gotta run. thanks for the metals!

Answer 19

oh okay thanks. I'll be needing more help in the future.

Answer 20

youll be getting more from me

Answer 21

there are lots of people willing to help. if you see me online you can tag me using @richyw