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maths help.... making x subject in a cubic polynomial....
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\[f(x)=x^3+2x^2-3x-11\]
show that f(x) =0 and can be rearranged as \[x=\sqrt{\frac{ 3x + 11 }{ x + 2 }} , x \neq -2\]
the last post is f(x) or just x?
it is x because the question is saying make x subject in the equation f(x)=0...
ok tell me this. do we have to prove f(x) as 0 or is it given that f(x) = 0 ? bcoz i dnt think u prove f(x) = 0 normally
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@Mertsj
bcoz if its already given that f(x) = 0 then this sum is actually quite easy..
\[x^3+2x^2-3x-11=0\] \[x^3+2x^2=3x+11\] \[x^2(x+2)=3x+11\] \[x^2=\frac{3x+11}{x+2}\] \[x=\sqrt{\frac{3x+11}{x+2}}\]
lol means f(x) WAS 0 ?
:) perfect!!
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thank you.....@luckythebest and @Mertsj
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