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Mathematics 9 Online
OpenStudy (anonymous):

maths help.... making x subject in a cubic polynomial....

OpenStudy (anonymous):

\[f(x)=x^3+2x^2-3x-11\]

OpenStudy (anonymous):

show that f(x) =0 and can be rearranged as \[x=\sqrt{\frac{ 3x + 11 }{ x + 2 }} , x \neq -2\]

OpenStudy (loser66):

the last post is f(x) or just x?

OpenStudy (anonymous):

it is x because the question is saying make x subject in the equation f(x)=0...

OpenStudy (anonymous):

ok tell me this. do we have to prove f(x) as 0 or is it given that f(x) = 0 ? bcoz i dnt think u prove f(x) = 0 normally

OpenStudy (loser66):

@Mertsj

OpenStudy (anonymous):

bcoz if its already given that f(x) = 0 then this sum is actually quite easy..

OpenStudy (mertsj):

\[x^3+2x^2-3x-11=0\] \[x^3+2x^2=3x+11\] \[x^2(x+2)=3x+11\] \[x^2=\frac{3x+11}{x+2}\] \[x=\sqrt{\frac{3x+11}{x+2}}\]

OpenStudy (anonymous):

lol means f(x) WAS 0 ?

OpenStudy (loser66):

:) perfect!!

OpenStudy (anonymous):

thank you.....@luckythebest and @Mertsj

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