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OpenStudy (anonymous):
ln e^(3-4x) hellppppp
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jimthompson5910 (jim_thompson5910):
same idea as last time ln(e^x) = x so... ln(e^(3-4x)) = 3 - 4x
OpenStudy (anonymous):
okay, now i see lol i didnt recognize it was the same problem..
jimthompson5910 (jim_thompson5910):
yeah just keep in mind or write it down that e^(ln(x)) = x and ln(e^x) = x
OpenStudy (anonymous):
\[3^{x+4}=7^{x-1}\]
OpenStudy (anonymous):
i have a lot of problem to solve like this i just needed help figuring out how to solve them
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jimthompson5910 (jim_thompson5910):
you take the natural log of both sides, then you use the rule: ln(x^y) = y*ln(x) \[\large 3^{x+4}=7^{x-1}\] \[\large \ln\left(3^{x+4}\right)=\ln\left(7^{x-1}\right)\] \[\large (x+4)\ln\left(3\right)=(x-1)\ln\left(7\right)\]
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