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Mathematics 7 Online
OpenStudy (anonymous):

Find the indicated sum for the geometric series. S6 for 2 +1 + 1/2 + 1/4 + ...

OpenStudy (anonymous):

okay, so here we just need to find 2 more terms, right? then add them all up!

OpenStudy (anonymous):

Okay. How would we find the next 2? @robz8

OpenStudy (anonymous):

well, since it is a geometric series, what is the pattern we see between each of the numbers?

OpenStudy (anonymous):

Its being subtracted? @robz8

OpenStudy (anonymous):

hmm noooo... not quite... remember, a geometric series means that we are multiplying each number by something to get the next number! what number number to we multiply to 2 to get 1? how about from 1 to 1/2?

OpenStudy (anonymous):

.5 @robz8

OpenStudy (anonymous):

exactly! so just keep multiplying the numbers by .5 (or 1/2) to get the next to numbers in the series!

OpenStudy (anonymous):

I got 1/8 and 1/16. @robz8

OpenStudy (anonymous):

And for my final answer, I got 63/16

OpenStudy (anonymous):

you are supposed to be adding up forever

OpenStudy (anonymous):

doesn't S6 determine that it is the summation up the the 6th term right?

OpenStudy (anonymous):

her syntax was a little confusing

OpenStudy (anonymous):

\[a+ar+ar^2+ar^3+ar^4+...=\frac{a}{1-r}\] ah i see, it does say \(S_6\) but then it has the \(...\) hmmm

OpenStudy (anonymous):

if it is six terms, add

OpenStudy (anonymous):

yeah if it was an infinite geometric series then it would be 2/(1-(1/2)), but i don't think that' what it's asking

OpenStudy (anonymous):

you are correct, it is 63/16. good job! @Emilyh117

OpenStudy (anonymous):

Thanks! :) @robz8

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