Question

how to get the derivative of 2^sin(x)

Answer 1

I am assuming you set it to y, and derive by taking the natural log to bring sinx down?

Answer 2

But I'm sure there is an easier way...

Answer 3

\[\frac{d}{dx}\left[a^{f(x)}\right]=a^{f(x)}f'(x)\ln(a)\]

Answer 4

So, (2^sinx)'=(2^sinx)(-cosx)ln2 ...?

Answer 5

yes

Answer 6

Lovely! Thank you very much.

Answer 7

no...cos(x)...not -cos(x)

Answer 8

OH hahaha my bad -_-' Thank you for the correction.

Answer 9

\[\frac{d}{dx}\sin(x)=cos(x)\]

Answer 10

Right. I knew that. :S Thanks! :D

Answer 11

Good catch by the way.

Answer 12

That's my job ;)