Question

how to solve integral of 5xsinxcosx

Answer 1

convert sinx cos x = 1/2 sin 2x first
then put it back to integral
let u = 2x
and ..... done

Answer 2

the leftover is not hard for you, I think so. of course it's not done as I state, but just some simple steps you can get the answer

Answer 3

I guess you'll need integration by parts.

Answer 4

wat answer did u guys get

Answer 5

What have you got?

Answer 6

massive answer

Answer 7

Type/write it here.

Answer 8

ok

Answer 9

so

Answer 10

@ramstar I don't have the answer, just wait for you.

Answer 11

so let =5x/2 v =sin(2x)

Answer 12

u'=5/2 and v' =2 cos (2x)

Answer 13

then i used this formula uv-integral u'v

Answer 14

is it right

Answer 15

I guess no?

Answer 16

Formula for integration by parts:\[\int u(x) v'(x) dx = u(x)v(x) - \int u'(x) v(x)dx\]

Answer 17

same thing right

Answer 18

Now, you've got \[\int \frac{5}{2}xsin2xdx\]To simpler manipulations, pull out the constant
\[=\frac{5}{2} \int xsin2xdx\]Now, what is u(x) and what is v'(x)?

Answer 19

x

Answer 20

x is u(x) or v'(x)?

Answer 21

u=x

Answer 22

*u(x) = x
So, what is v'(x)?

Answer 23

2cos 2x

Answer 24

-

Answer 25

Nope..

Answer 26

why