Question

find the measure of an angle whose supplement measures seventeen times its measure

Answer 1

Hmm so let's see.
If angles are supplementary, they add up to \(\large 180^o\) right?

`find the measure of an angle`, let's call this angle \(\large x\).
`whose supplement`, hmm let's come up with an equation for the supplement.

I guess we can call it.... \(\large s\) maybe..? :P

If x and s are supplementary, they add up to 180. \(\large x+s=180^o\)
So if we want an equation for the supplementary angle, we can write it as, \(\large 180^o-x=s\)

`whose supplement measures seventeen times its measure`
this wording is really confusing. I guess what they're saying is,
who's supplement equals 17 times the original angle measure.
Which we can write like this \(\large s=17x\).

And we're trying to solve for x.

Answer 2

ok. I see let's see if I can figure it out now.

Answer 3

so x = 18 degrees

Answer 4

\[\large \color{green}{s=180^o-x}\]

\[\large \color{green}{s}=17x \qquad \rightarrow \qquad \color{green}{180-x}=17x\]

Which simplifies down to,\[\large 180=18x \qquad \rightarrow \qquad x=\frac{180}{18}\]

Do these steps look the same as yours?
I think maybe you just messed up the division at the end :o

Answer 5

Yup I messed up division its 10. Thanks. This problem is confusing though. I will try some similar ones and see if I can do them based on this example. Thanks again!

Answer 6

Cool c: