Question

At what depth from the surface of the earth is the value of acceleration due to gravity one-fourth the value at the earth's surface ?

Answer 1

g'=g[1-(d/R)]..
g'=g/4
find d, where d is the depth.

Answer 2

it'll be 3/4 of r ie 4800 km below the surface.

Answer 3

how??

Answer 4

i just gave you the formula.. solve it.

Answer 5

g' = GM / (R+h)^2

Answer 6

^^ is this the formula ?

Answer 7

coz that formula is not available in my book

Answer 8

nope this is the formula for a height h above the earth. you have to find g at a depth d below the earth.

Answer 9

g'= g-gd/R

Answer 10

yup..

Answer 11

this is given in my book for depth

Answer 12

use this.

Answer 13

the answer is coming 4785000 is this correct ?

Answer 14

i havent solved it. its easy calculations. or else use a calculator to check your answer.

Answer 15

plz tell me is this correct using your on screen calculator plzz

Answer 16

3/4*R =3/4*6400=3*1600=4800kms.

Answer 17

how did you get 4785000?

Answer 18

g' = 9.8/4

Answer 19

g' = 2.45

Answer 20

2.45 = 9.8 - 9.8d/6.38x10^6

Answer 21

its simple put g'=g/4 and g cancels out on both sides.we are left with 1/4=1-d/r.then solve it

Answer 22

how come g' cancels with g ??

Answer 23

oh dear put g'=g/4 so g cancels out not g'

Answer 24

can u draw and show me :)