Question

Please help with this question! It's to help me study for my final exam.

(Note: use algebra to solve this problem) In 1933, the life expectancy of males was 72.2 years. In 2003, it was 74.8 years. Let E(t) represent life expectancy and t the number of years since 1933. Find a linear function that fits the data.

Answer 1

E(t)=\[(13t+3613)/50\]

Answer 2

Can you show me the steps please?

Answer 3

the equation of a straight line is \[(y'-y'')/(y''-y)=(x'-x'')(x''-x)\]
Here (x',y') represent the year 1993 and the life expectancy 72.2
And (x'',y'') represent the year 2003 and the lifeexpectancy 74.8
(x,y) represent any point on the line.
You will get an equation like this after plugging in the values:-
\[y=(13x-22296)/50\]

Now, x represents a year, and we require the equation based on 't' i.e., difference in years..so substitute 'x' as (1993+t) and 'y' with E(t)..
Remove the brackets....