Question

Factor completely
12n3-3n2+16n-4


The 3 after 12n is an exponent and so is the 2 after 3n. Please show me work

Answer 1

\[12n^2 - 3n^2 + 16n - 4\]

Answer 2

You want to start off by adding your squared terms.

Answer 3

12n is cubed

Answer 4

Yes, it is :P I failed

Answer 5

Lol thanks

Answer 6

\[(3n^2 + 4)(4n - 1)\]

Answer 7

How'd you get that?

Answer 8

I factored the two terms that will make \[12n^3 = 3n^2 + 4n\]

I also had to make sure that I got \[-3n^2\], so I had to place a negative -1 at the outer part of my binomial. After you get those terms, it's all down hill from there. The equation should fall into place. There is no mathematical method to factoring, you just have to logically deduct what you see.