Simplify: ln [(3x^3 + sin2x)^(1/3)]
Much of it depends on what you regard as simple... \[\Large \ln\left[(3x^3 + \sin \ 2x )^{\frac13}\right]\]
For one thing, you can bring the exponent down, as per the properties of logarithms... \[\Large \frac13\ln(3x^3 + \sin \ 2x )\]
I don't see how it can be simplified further from here...
That's the answer that the teacher gave, but I don't understand why the 1/3 is put in front of the ln, rather than distributed within the argument.
You can do that, but isn't what I'd call "simplify", since the expression would look more complicated. Also, one does not simply distribute a fractional exponent, it'd be like \[\Large \sqrt[3]{3x^3+ \sin \ 2x}\] and we don't really distribute the radical...
I don't know why my brain won't accept that you can't simply distribute an exponent within a parenthetical expression. Thanks for the explanation.
No problem :)
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