Ask your own question, for FREE!
Mathematics 17 Online
OpenStudy (anonymous):

Answer the following questions about the function whose derivative is given below. f′(x)=(x−5)^2(x+7) a. what are the critical points of f? b. On what intervals is f increasing or decreasing? c. at what points, if any, does f assume local maximum and minimum values?

OpenStudy (anonymous):

sorry bro , takes time to explain

OpenStudy (anonymous):

It's okay, I want to understand it so take your time

OpenStudy (rajee_sam):

Critical points are those where the slope = 0 ( aka The derivative does not exist). So to find the critical point put derivative = 0 and find values of x. \[(x-5)^{2}(x+7) = 0 \] x = 5, 5 , -7

OpenStudy (anonymous):

Okay, but how do you tell where they're increasing or decreasing?

OpenStudy (rajee_sam):

I am having server problem , my connection is very slow, stay in touch I will explain everything shortly

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

3(x^2-2x-15)

OpenStudy (rajee_sam):

A function is increasing in an interval if its first derivative is poitive in that interval. i.e (f'(x) > 0) . A function is decreasing in an interval if its first derivative is negative in that interavl. i.e. (f'(x) < 0 ) Since we know our critical values where our derivative is zero we set up the intervals and give test values in each interval to determine the sign of the derivative.

OpenStudy (rajee_sam):

|dw:1367680288670:dw|

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!