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Mathematics 19 Online
OpenStudy (anonymous):

find derivative

OpenStudy (anonymous):

\[y=5-\theta^7\cos\]

OpenStudy (anonymous):

would it be 7\[7\theta^6-\sin\]

OpenStudy (anonymous):

Do you mean: \(y = 5 - cos^{7}(\theta)\) ??

OpenStudy (rajee_sam):

\[y = 5 - \cos ^{7} \theta\]]

OpenStudy (anonymous):

no the problem is exactly like this \[y=5-\theta^7\cos \theta\]

OpenStudy (anonymous):

Oh okay.. And you have to find derivative with respect to x or theta??

OpenStudy (rajee_sam):

what? where is the x here?

OpenStudy (anonymous):

so would that turn in to \[y=5-\cos \theta^8\]

OpenStudy (anonymous):

Oh God.. There is no x..

OpenStudy (anonymous):

with respect to theta. there is no x here.

OpenStudy (anonymous):

\[\theta^7 \cdot \cos(\theta)\] Here to find its derivative you will use Product rule..

OpenStudy (anonymous):

would the derivative be \[y= -8 \sin \theta^7\]

OpenStudy (anonymous):

But there is one - outside.. Yep that is right..

OpenStudy (anonymous):

\[\large Derivative(u \cdot v) = u \cdot v' + v \cdot u'\]

OpenStudy (rajee_sam):

\[\frac{ dy }{ d \theta } = - (7\theta ^{6} Cos \theta - \theta ^{7} Sin \theta )\]

OpenStudy (anonymous):

y = 5 - (cos x)^7 y' = -7(cos x)^6(-sin x)

OpenStudy (anonymous):

ok I understand. Used the quotient rule right

OpenStudy (anonymous):

thanks

OpenStudy (rajee_sam):

it is very confusing what the actual problem is everytime billie is writing something else

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