A man standing at a point P on a flat plane starts walking. At each step, he walks exactly 1 foot in one of the directions N,S,E or W. Suppose that after 6 steps he comes back to P, then no. of distinct paths he can take is ? a) 196 b)256 c)344 d)400
I have attempted this and am getting 384 as the answer. But 384 is not even in the options -_- I'll post my attempt below
lets divide 6 steps into 2 cases first 3 and last 3 for him to be back at original pos there should be 3 counter steps E and W are counter N and S are counter for 1st 3 steps he has 4 options of each step so 4*4*4 =64 now for last 3 steps, we need 3 counter steps .. the 3 counter steps can be at any position.. so 3! i.e. 6 final ans acc to me should have been 64*6 = 384 but thats wrong where am I going wrong ?
u have 288 in options ?
I have posted the options no, 288 is not there @ganeshie8
seems like I am getting 404 http://www.wolframalpha.com/input/?i=Sum%5BBinomial%5B3%2Ck%5D%5E2%2C%7Bk%2C+0%2C+3%7D%5D*4+%2B4*9%5E2
woops!! i counted double ... 400
please explain your logic sir :O yes 400 is the right ans
just consider the position of third step.
|dw:1367690410952:dw| x is where your possible third step is
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