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Mathematics 15 Online
OpenStudy (anonymous):

differentiate

OpenStudy (anonymous):

\[f(x)=\sqrt{12x-x^7}\]

OpenStudy (anonymous):

The rule for the square root is :\[(12x-x^2)'/2\sqrt{12x-x^2}\]

OpenStudy (anonymous):

sorry x^7 not 2

OpenStudy (anonymous):

now can you differentiate (12x-x^7) ?? @ billie4120

OpenStudy (anonymous):

@billie4120

OpenStudy (anonymous):

you there @billie4120 ??

OpenStudy (anonymous):

I thought it was \[\frac{ 1 }{ 2(12x-x^7)^{1/2} }\]

OpenStudy (anonymous):

yes you're right but (12x - x^7) is a function so you have to differentiate this as well

OpenStudy (anonymous):

This is the chain rule

OpenStudy (anonymous):

do you understand it?

OpenStudy (anonymous):

Ok let me know if you need help @billie4120

OpenStudy (anonymous):

do I just take the derivative of 12x-x^7

OpenStudy (anonymous):

yes and then divided by the 2sqrt(...)

OpenStudy (anonymous):

so would it be \[\frac{ 1 }{ 2\sqrt{12-7x^6} }\]

OpenStudy (anonymous):

No I said the derivative of the function divided by the double of the square root

OpenStudy (anonymous):

got it??

OpenStudy (anonymous):

not sure \[\frac{ 12-7x^6 }{ 2(12x-x^7)^{1/2} }\]

OpenStudy (anonymous):

that so true Good job

OpenStudy (anonymous):

that's it?

OpenStudy (anonymous):

yea

OpenStudy (anonymous):

except of you have initial values for x ??

OpenStudy (anonymous):

no there are no values for x Thank you.

OpenStudy (anonymous):

ok so that is it!! and you are welcome

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