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OpenStudy (anonymous):
differentiate
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OpenStudy (anonymous):
\[f(x)=\sqrt{12x-x^7}\]
OpenStudy (anonymous):
The rule for the square root is :\[(12x-x^2)'/2\sqrt{12x-x^2}\]
OpenStudy (anonymous):
sorry x^7 not 2
OpenStudy (anonymous):
now can you differentiate (12x-x^7) ?? @ billie4120
OpenStudy (anonymous):
@billie4120
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OpenStudy (anonymous):
you there @billie4120 ??
OpenStudy (anonymous):
I thought it was
\[\frac{ 1 }{ 2(12x-x^7)^{1/2} }\]
OpenStudy (anonymous):
yes you're right but (12x - x^7) is a function so you have to differentiate this as well
OpenStudy (anonymous):
This is the chain rule
OpenStudy (anonymous):
do you understand it?
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OpenStudy (anonymous):
Ok let me know if you need help @billie4120
OpenStudy (anonymous):
do I just take the derivative of 12x-x^7
OpenStudy (anonymous):
yes and then divided by the 2sqrt(...)
OpenStudy (anonymous):
so would it be
\[\frac{ 1 }{ 2\sqrt{12-7x^6} }\]
OpenStudy (anonymous):
No I said the derivative of the function divided by the double of the square root
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OpenStudy (anonymous):
got it??
OpenStudy (anonymous):
not sure
\[\frac{ 12-7x^6 }{ 2(12x-x^7)^{1/2} }\]
OpenStudy (anonymous):
that so true
Good job
OpenStudy (anonymous):
that's it?
OpenStudy (anonymous):
yea
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OpenStudy (anonymous):
except of you have initial values for x ??
OpenStudy (anonymous):
no there are no values for x
Thank you.
OpenStudy (anonymous):
ok so that is it!! and you are welcome
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