Question

Solve for x, Show your work

Answer 1

\[\sqrt{x+2}+4=x\]

Answer 2

The first step u have to do in problems like this is to get rid of the sqrt. this can be done by squaring both sides.
\(\sqrt{x+2}+4=x\)
\(\sqrt{x+2}=x-4\)
\((\sqrt{x+2})^2=(x-4)^2\)
\(x+2=x^2-8x+16\)
\(x^2-8x-x+16-2=0\)
\(x^2-9x+14=0\)
Use quadratic formula to find x.
\[x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\]
the values of a, b nd c can be found by comparing the equation \(x^2-9x+14=0\) with
the general equation \(ax62+bx+c=0\).
Does that help? @BrainsNThings

Answer 3

*\(ax^2+bx+c=0\)