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find the exact value: arcsin (sqrt(3))/2
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Do you know what value of sin is sqrt{3}/2 ??
whoops, I mean arcsin (sqrt(3)/2)
Answer above question..
\[\sin^{-1} \frac{ \sqrt{3} }{ 2 }\]
pi/3
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Yep..
That's what I thought it was, it just seemed like too easy a question for the final. Thanks.
\[\sin^{-1}(\frac{\sqrt{3}}{2}) \implies \sin^{-1}(\sin \frac{\pi}{3}) \implies \frac{\pi}{3}\]
I understand the answer as it relates to the unit circle, but the second operation in that chain confuses me.
It is okay..
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\[\sin^{-1}(\sin(x)) = x\]
Okay, thanks.
You are welcome dear..
You know that sin{pi/3) = sqrt{3}/2, so in second step we are just placing this value in place of sqrt{3}/2..
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