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Mathematics 13 Online
OpenStudy (anonymous):

Find x. http://www.usatestprep.com/modules/gallery/files/44/4463/4463.png

OpenStudy (anonymous):

It will go like: \[4(4+5) = 3(3+x)\] Find x here..

OpenStudy (anonymous):

Can you do the calculations here?

OpenStudy (anonymous):

will x be 9

OpenStudy (anonymous):

Yep.. Good..

OpenStudy (anonymous):

i have another question

OpenStudy (anonymous):

Okay, go ahead..

OpenStudy (anonymous):

Find the midpoint of the segment connecting (4,7) to (-2,3).

OpenStudy (anonymous):

Take the average of x coordinates...

OpenStudy (anonymous):

What is average of 4 and -2?

OpenStudy (anonymous):

is it 2

OpenStudy (anonymous):

4-2 = 2.. But don't forget you will divide it again by 2.. as there are two observations..

OpenStudy (anonymous):

\[x = \frac{x_1 + x_2}{2}\]

OpenStudy (anonymous):

\[y = \frac{y_1 +y_2}{2}\]

OpenStudy (anonymous):

is it (1,5)

OpenStudy (mayliz):

@waterineyes how you find that 4(4+5)=3(3+x) ?

OpenStudy (anonymous):

@mayliz |dw:1367689781315:dw|

OpenStudy (anonymous):

Yes (1,5) is right.. Good..

OpenStudy (anonymous):

What is the length of http://www.usatestprep.com/modules/gallery/files/18/1876/1876.pngline segment JK?

OpenStudy (anonymous):

The page you are looking for cannot be found.

OpenStudy (anonymous):

Where is the line cutting the x axis??

OpenStudy (anonymous):

at 0

OpenStudy (anonymous):

Is that 0? I don't think so..

OpenStudy (anonymous):

is the answer 106

OpenStudy (anonymous):

Use pythagorean theorem here..

OpenStudy (anonymous):

|dw:1367690577576:dw|

OpenStudy (anonymous):

\[c^2 = 5^2+9^2\]

OpenStudy (anonymous):

Just take the square root, you forgot there..

OpenStudy (anonymous):

i thought you would use D= (x2 - x1)2 + (y2 - y1)2

OpenStudy (anonymous):

Just one and the same thing.

OpenStudy (anonymous):

You are forgetting square root there.. \[D = \sqrt{(x_2-x_1)^2 + (y_2 -y_1)^2}\]

OpenStudy (anonymous):

the answer is 19

OpenStudy (anonymous):

How??

OpenStudy (anonymous):

J(-2,4) and K(5,-3) Now, find the distance properly..

OpenStudy (anonymous):

Sorry J(-4,2) and K(5,-3)..

OpenStudy (anonymous):

13

OpenStudy (anonymous):

Guessing??

OpenStudy (anonymous):

Just use that formula buddy.. Where are you getting confused?? \(x_2 = 5, x_1 = -4, y_2 = -3, y_1 = 2\)

OpenStudy (anonymous):

(-4,2) is 2 then you square root is which is 4

OpenStudy (anonymous):

Nope..

OpenStudy (anonymous):

Do, \((x_2-x_1)\) first.. What you got?

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