Question

is sine function (sin x) continuous at x= infinity ?

Answer 1

the function is defined everywhere

Answer 2

so, continuous everywhere?

Answer 3

trust your heart

Answer 4

LHL at infinity gives u a -ve value of Sinx
But RHL at infinity gives u a +ve value of SInx

Answer 5

lol, i will, thanks :)

Answer 6

how ? @lordcyborg ?

Answer 7

coz u'll take LHL at minus infinity and RHL at plus infinity and Sin(-x) = -Sinx

Answer 8

sin (infinity) or sin(-infinity) can be any number between 1 and -1

Answer 9

good job

Answer 10

what about sin (pi x/ (2-3x)) ??
is this also continuous at x= infinity ?

Answer 11

But Sin(infinity) gives a +ve value and Sin(-infinity) gives a -ve value

Answer 12

@primeralph
what about sin (pi x/ (2-3x)) ?? is this also continuous at x= infinity ?

Answer 13

See in this if u put x=infinity u'll have to check continuity by Limits(to be damn sure), so i think u'll still get the answer as discontinuous as i have stated it earlier

Answer 14

so, if that limit exist, its continuous ?

Answer 15

ya @gohangoku58

Answer 16

range of sin is -1 to 1 ,so for any value it will be defined ...
for sin(pi x/(2-3x)) solve like this
sin (pi /(2/x)-3) this will reduce to sin(pi/(-3)) only

Answer 17

Woah!!!!

Answer 18

i thought so! :) thanks :)