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logarithmic functions
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Prove that \[\frac{ lnx }{ xln10 } + \frac{ logx }{ x }\] = \[\frac{ 2lnx }{ xln10 }\]
use the change of base formula to change log x to ln x
I assume log x means log base 10 x
i forgot...i m doing derivatives and i got the first answer...book says the first answer can be solved to second one...i just dont remember log functions anymore
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\[ \log x = \frac{\ln x}{\ln(10)} \]
he's correct
nm got it thx
you could use a calculator and check. most calculators do both natural log and log base 10
$$ \cfrac{\cfrac{ln(x)}{ln(10)}}{x} \implies \cfrac{ln(x)}{xln(10)} $$
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yes, and you get your result
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