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Use l’Hopital’s rule to show that f is continuous at x=-1.
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I worked out that the limit at x=-1 is \[\frac{ \ln(b) }{ \ln(a) }\]. but this is only near x=-1 not at x=-1
I mean, the limit is this: http://www.wolframalpha.com/input/?i=limit+as+%28%282%5E%28x%2B1%29-3%5E%28x%2B1%29%29%2F%28x%2B1%29%29+x-%3E-1#_=_
differentiate the first piece top and bottom, plug in -1.
ye, i did that. my question is its the limit as x approaches -1. l’Hopital’s will give the derivative as x approches -1. However, this says nothing about the point AT x = -1. if might not be defined, thats the question
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