Question

Find the position function s(t) from the given velocity or acceleration function and initial value(s). Assume that units are feet and seconds. v(t) = 40 – sin t, s(0) = 2

Answer 1

Position Function: \(x(t) = \int\limits_{0}^{t}v(r)\;dr\) Go!

Answer 2

I got -1 is that correct?

Answer 3

No, it should have a 't' in it.

What did you get for \(\int 40 - \sin(t)\;dt\)

Answer 4

I got (40 - sin(t)) (x)

Answer 5

dt not dx.

Answer 6

Maybe \(x(t) = 40t + \cos(t) + C\)

Answer 7

ok

Answer 8

then i substitute 2 right?

Answer 9

Sorry, I've been using x(t). I see the problem statement has specified s(t).

\(s(t) = 40t + \cos(t) + C\)

No, substitute t = 0, so that s(0) = 2. This establishes the values of "C".

Answer 10

ohh okay got you