Question

How do you solve this differential equation: (x^3)y''+(x^2)y'-xy=x?

Answer 1

\[\large x^3y''+x^2y'-xy=x\]Divide through by \(\large x\),\[\large x^2y''+xy'-y=1\]The complimentary solution \(\large y_c\) is given by,\[\large x^2y''+xy'-y=0\]I think this part shouldn't be too difficult, it's a Cauchy Euler Equation.
Do you know how to solve those? :o

Answer 2

No, we haven't gone over them yet.

Answer 3

Hmm :o

Answer 4

That's ok. I was just running through some practice problems and happened upon this one, though nothing like it was taught in the lesson. So it's not critical :) Thanks for your help, though. I'm going to be logging out pretty soon.

Answer 5

ah i see c: